AP Biology · Unit 2 · 10–13% of Exam

The Cell

The cell is the fundamental unit of life. Unit 2 covers everything from organelle structure and function, to how membranes control what enters and exits cells, to the evolutionary origin of the eukaryotic cell. Membrane transport — especially osmosis — is the highest-tested topic in this unit.

Prokaryotes vs. Eukaryotes Organelles Surface Area:Volume Fluid Mosaic Model Diffusion & Osmosis Tonicity Active Transport Endosymbiosis
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Topic 2.1

Cell Structure and Function

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All cells share four features: (1) a plasma membrane, (2) cytoplasm, (3) DNA as genetic material, and (4) ribosomes. Beyond these fundamentals, cells are broadly classified into two cell types: prokaryotic (no membrane-bound nucleus) and eukaryotic (membrane-bound nucleus and organelles). Note: "domain" is a taxonomic rank — the three domains of life are Bacteria, Archaea, and Eukarya, not prokaryote/eukaryote.

Prokaryotes vs. Eukaryotes

FeatureProkaryoteEukaryote
NucleusAbsent; DNA in nucleoid region (not membrane-bound)Present; DNA enclosed in nuclear envelope (double membrane)
DNA structureSingle circular chromosome; often has plasmidsMultiple linear chromosomes; associated with histone proteins
Membrane-bound organellesAbsentPresent (mitochondria, ER, Golgi, etc.)
Ribosomes70S (smaller)80S in cytoplasm; 70S in mitochondria/chloroplasts
Cell wallUsually present (peptidoglycan in bacteria)Plants: cellulose; Fungi: chitin; Animals: absent
Size1–10 μm10–100 μm
ExamplesBacteria, ArchaeaPlants, Animals, Fungi, Protists

Key Eukaryotic Organelles — Structure Dictates Function

Information
🔵 Nucleus

Contains DNA; site of transcription (DNA → mRNA). Enclosed by nuclear envelope (double membrane with pores). Nuclear pores control movement of mRNA, proteins, and ribosomal subunits.

Information
🔵 Nucleolus

Dense region within the nucleus; site of rRNA synthesis and ribosome subunit assembly. Not membrane-bound. Larger and more active in cells that produce many proteins.

Protein Synthesis
🟣 Ribosomes

Site of translation (mRNA → protein). Free ribosomes in cytoplasm make proteins for the cell interior. Ribosomes on the rough ER make proteins for secretion, the membrane, or lysosomes.

Protein Processing
🟣 Rough ER

Studded with ribosomes. Receives newly synthesized proteins; performs initial protein folding and glycosylation. Manufactures membrane lipids. Continuous with nuclear envelope.

Lipid/Detox
🟣 Smooth ER

No ribosomes. Functions: lipid synthesis (phospholipids, steroids), detoxification of drugs/toxins (abundant in liver cells), calcium storage (in muscle cells — triggers contraction).

Protein Processing
🟡 Golgi Apparatus

"Post office" of the cell. Receives vesicles from ER (cis face), modifies and packages proteins (glycosylation, phosphorylation), then ships to destinations via vesicles (trans face) — lysosomes, plasma membrane, or secretion.

Digestion
🔴 Lysosomes

Contain hydrolytic enzymes (hydrolases) at pH ~5. Digest worn organelles (autophagy), cellular debris, food particles, pathogens. Found only in animal cells. If lysosomes rupture, the cell self-digests.

Energy
🟢 Mitochondria

Site of cellular respiration (produces most ATP). Double membrane: outer membrane + highly folded inner membrane (cristae) which maximizes surface area for ATP synthase. Matrix contains circular DNA, ribosomes (70S) — evidence for endosymbiosis.

Energy
🟢 Chloroplasts

Site of photosynthesis. Double membrane + internal membrane system of thylakoids (stacked grana). Stroma surrounds thylakoids. Contains circular DNA, 70S ribosomes — also evidence for endosymbiosis. Only in plants and some protists.

Structural
⚪ Vacuoles

Large central vacuole in plant cells: maintains turgor pressure, stores water/ions/pigments. In animal cells: smaller, used for storage or waste. In protists: contractile vacuoles expel excess water (osmoregulation).

Structural
⚪ Cytoskeleton

Network of protein filaments: microfilaments (actin — cell shape, amoeboid movement), microtubules (tubulin — chromosome separation in mitosis, cilia/flagella structure, vesicle transport), intermediate filaments (structural support, anchor organelles).

Cell Wall
🌿 Cell Wall (Plants)

Made of cellulose microfibrils. Provides rigid support, prevents excessive water uptake (limits cell swelling). Freely permeable to water and small molecules — does NOT restrict diffusion the way the plasma membrane does.

High-Frequency Exam Points

Secretory pathway: Ribosomes (on rough ER) → ER lumen → transport vesicle → Golgi (cis face) → modified → vesicle → plasma membrane (exocytosis) or lysosome. Know this sequence cold — it appears in FRQs about how a secreted protein gets from DNA to outside the cell.

Mitochondria and chloroplasts have 70S ribosomes and circular DNA — just like bacteria. This is the evidence for the endosymbiotic theory. The exam will ask you to "support or refute" endosymbiosis using this evidence.

Structure → function: Cells with high secretory activity (e.g., pancreatic cells, antibody-producing B cells) have abundant rough ER and Golgi. Muscle cells have abundant smooth ER (calcium store). Liver cells have abundant smooth ER (detoxification). Always connect organelle abundance to cell function.

FRQ-Style · Topic 2.1

A scientist studying a newly discovered unicellular organism finds it has circular DNA, 70S ribosomes, no nuclear envelope, and no membrane-bound organelles. Describe whether this organism is prokaryotic or eukaryotic, and justify your answer using TWO pieces of evidence.

Classification: Prokaryote

Evidence 1 — No nuclear envelope: In prokaryotes, DNA is not enclosed within a membrane-bound nucleus. The organism's DNA is in a nucleoid region open to the cytoplasm. Eukaryotes always have a double-membrane nuclear envelope surrounding their chromosomes.

Evidence 2 — Circular DNA + 70S ribosomes: Prokaryotes have a single, circular chromosome (no linear chromosomes with histones). Their ribosomes are 70S, smaller than eukaryotic cytoplasmic ribosomes (80S). Both features match the prokaryotic cell type.
Topic 2.2

Cell Size

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Why can't cells simply keep growing larger? The answer lies in the surface area-to-volume ratio (SA:V). As a cell grows, its volume increases much faster than its surface area. A cell's plasma membrane (surface area) is its interface for exchanging nutrients, gases, and wastes with the environment. If volume becomes too large relative to surface area, the cell can no longer sustain the metabolic demands of its interior.

The Math of SA:V

For a cube of side length s: Surface Area = 6s², Volume = s³, SA:V = 6/s. As s increases, SA:V decreases. This means larger cells are less efficient at exchange.

Cube Side (μm)Surface Area (μm²)Volume (μm³)SA:V Ratio
1616.0
22483.0
496641.5
83845120.75

Cells maintain high SA:V by staying small, or by adopting shapes that maximize surface area: microvilli (intestinal epithelium), highly folded cristae (mitochondria), and flattened thylakoid membranes (chloroplasts) are all adaptations that increase membrane surface area relative to volume.

High-Frequency Exam Points

SA:V calculation: The AP exam frequently provides a data table or asks you to calculate SA:V for cells of different sizes. Know the formulas for cubes AND spheres (SA = 4πr², V = ⁴⁄₃πr³). Always show your work and include units.

Applying SA:V to biology: Small intestine villi/microvilli increase SA for absorption. Alveoli in lungs are small and spherical — high SA for gas exchange. Neurons are elongated — connects to function, not SA:V per se. Flat red blood cells maximize SA for oxygen loading.

Prediction questions: "Which cell will reach equilibrium with a dye faster — a 1mm cube or a 3mm cube?" → The smaller cube (higher SA:V). Slower equilibration = larger cube.

MCQ · Topic 2.2

A spherical cell has a radius of 2 μm. If the cell doubles its radius to 4 μm, what happens to its surface area-to-volume ratio?

  • (A) It doubles, because the surface area doubles.
  • (B) It decreases by half, because volume increases proportionally faster than surface area.
  • (C) It stays the same, because both surface area and volume increase proportionally.
  • (D) It increases by half, because the surface area increases faster than volume.
Answer: (B) — At r=2: SA = 4π(4) = 50.3 μm²; V = ⁴⁄₃π(8) = 33.5 μm³; SA:V ≈ 1.5. At r=4: SA = 4π(16) = 201.1 μm²; V = ⁴⁄₃π(64) = 268.1 μm³; SA:V ≈ 0.75. The ratio halved. When radius doubles, SA increases by 4× but volume increases by 8×, so SA:V decreases by half.
Topic 2.3

Plasma Membrane

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The plasma membrane is described by the Fluid Mosaic Model (Singer & Nicolson, 1972). "Fluid" because phospholipids and proteins can move laterally within the bilayer — the membrane is not a rigid structure. "Mosaic" because proteins of various types are embedded in or attached to the lipid bilayer, creating a mosaic appearance.

Membrane Composition

🫧 Phospholipid Bilayer

The structural foundation. Hydrophilic phosphate heads face outward (toward water); hydrophobic fatty acid tails face inward. Spontaneously forms bilayer in water. Selectively permeable — allows small nonpolar molecules to pass freely; blocks large polar/charged molecules.

🔴 Integral Proteins

Embedded within or spanning the entire bilayer (transmembrane proteins). Functions: channel proteins (pores for ions), carrier proteins (transport), receptor proteins, enzymes. The hydrophobic portion is embedded in the lipid tails; hydrophilic portions face water.

🟠 Peripheral Proteins

Attached to the surface of the membrane (inner or outer face) — not embedded in the lipid bilayer. Functions: cell signaling, structural support (connect to cytoskeleton), enzymes. Easily removed by changing salt concentration.

🟡 Cholesterol

Intercalated between phospholipid molecules. Fluidity buffer: at high temperatures, reduces fluidity (prevents membrane from becoming too fluid); at low temperatures, prevents membrane from solidifying. Amount varies by organism and temperature adaptation.

🟢 Glycoproteins / Glycolipids

Carbohydrate chains attached to proteins or lipids on the outer face of the membrane. Form the glycocalyx — involved in cell-cell recognition, immune response (self vs. non-self), cell adhesion, and signal reception. ABO blood type antigens are glycoproteins/glycolipids.

Factors Affecting Membrane Fluidity

FactorEffect on FluidityBiological Relevance
↑ Temperature↑ Fluidity (more kinetic energy → lipids move more)Fever, fever-reducing drugs affect membrane function
↑ Unsaturated fatty acids↑ Fluidity (kinks prevent tight packing)Cold-water fish, deep-sea organisms have more unsaturated lipids
↑ Cholesterol (warm temps)↓ Fluidity (fills gaps between lipids)Stabilizes membrane, prevents excessive movement
↑ Cholesterol (cold temps)↑ Fluidity (disrupts crystal-packing of saturated lipids)Prevents membrane from becoming too rigid at low temp
Shorter fatty acid tails↑ Fluidity (less surface area for van der Waals forces)Bacteria regulate fatty acid chain length for homeoviscous adaptation
Common Mistakes

The membrane is not static. Individual phospholipids and most proteins can move laterally (flip-flop between layers is rare and slow). This lateral movement is key to understanding protein clustering and signal transduction.

Glycoproteins face OUTWARD only. Carbohydrate chains of glycoproteins/glycolipids are always on the extracellular face — they are synthesized that way in the ER/Golgi. They are never on the cytoplasmic face.

Topic 2.4

Membrane Permeability

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The plasma membrane is selectively permeable — it allows some substances to cross freely while restricting others. This selectivity is determined by the size, charge, and polarity of the molecule attempting to cross.

Rules for Membrane Crossing

Molecule TypeExampleCan Cross Freely?Reason
Small nonpolarO₂, CO₂, N₂✅ Yes (simple diffusion)Dissolve easily in hydrophobic lipid tails; small enough to slip through
Small uncharged polarH₂O, ethanol, urea⚠️ Slowly (or via aquaporins for water)Small size helps, but polarity slows crossing through hydrophobic core
Ions (any charge)Na⁺, K⁺, Cl⁻, Ca²⁺❌ No (need channels)Charge makes them strongly attracted to water (hydration shell) — cannot enter nonpolar core
Large polar moleculesGlucose, amino acids❌ No (need carriers)Too large and/or polar to diffuse through lipid bilayer
MacromoleculesProteins, polysaccharides, DNA❌ No (need vesicles)Far too large; require endo/exocytosis

Aquaporins — Water Channels

Although water is small and uncharged, its high polarity makes diffusion across the lipid bilayer slow. Aquaporins are integral membrane proteins that form water-specific channels, dramatically accelerating water movement. They are critical in the kidneys (water reabsorption), plant roots (water uptake), and red blood cells. Aquaporin discovery won the 2003 Nobel Prize in Chemistry.

High-Frequency Exam Points

"Why can't glucose cross the membrane by simple diffusion?" — Glucose is a large, polar molecule. Even though it has no net charge, its many –OH groups make it hydrophilic, and its size prevents it from fitting between phospholipid molecules.

Steroid hormones cross membranes; protein hormones do not. This distinction is tested in Unit 4 (Cell Communication). Steroids are nonpolar lipids → they freely diffuse across the membrane and bind intracellular receptors. Protein hormones are large polar → they bind surface receptors and initiate signal transduction cascades.

Topic 2.5

Membrane Transport — Passive Transport

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Passive transport moves substances across a membrane down their concentration gradient (from high to low concentration). It requires no energy (ATP) — the movement is driven by the concentration gradient itself (a thermodynamically favorable process). The two types are simple diffusion and osmosis.

Simple Diffusion

Direct movement of small nonpolar molecules (O₂, CO₂, lipids, steroids) through the phospholipid bilayer without any protein assistance. Rate of diffusion is determined by:

Osmosis — Diffusion of Water

Osmosis is the diffusion of water across a selectively permeable membrane, moving from a region of higher water potential (lower solute concentration / hypotonic) to a region of lower water potential (higher solute concentration / hypertonic). Water moves to equalize solute concentrations on both sides.

Key concept: Water moves toward the side with more solute — or equivalently, toward the side with lower water concentration. Think of it as water "following" solutes.

Water Potential (Ψ)

Water potential (Ψ) determines the direction of water movement. Ψ = Ψs + Ψp, where Ψs = solute potential (always negative — solutes lower water potential) and Ψp = pressure potential (turgor pressure in plant cells, usually positive).

Water always flows from higher Ψ to lower Ψ. Pure water has Ψ = 0 (reference point). Adding solutes makes Ψ more negative. Applying pressure makes Ψ more positive.

In plant cells: As water enters by osmosis, turgor pressure builds (Ψp increases), raising Ψ. Equilibrium is reached when Ψinside = Ψoutside.

MCQ · Topic 2.5

A cell with a solute potential of −8 bars and a pressure potential of +3 bars is placed in a solution with a water potential of −4 bars. In which direction will water move?

  • (A) Water will move out of the cell, because the cell's water potential is lower than the solution's.
  • (B) Water will move into the cell, because the solution has a higher water potential than the cell.
  • (C) No net water movement, because the solute potentials are equal.
  • (D) Water will move out of the cell, because the pressure potential is positive.
Answer: (B) — Step 1: Calculate cell water potential: Ψcell = Ψs + Ψp = −8 + 3 = −5 bars. Step 2: Solution Ψ = −4 bars. Step 3: Compare — the solution (−4) has a higher water potential than the cell (−5), because −4 > −5 (less negative = higher). Step 4: Water always moves from higher Ψ → lower Ψ, so water moves from the solution into the cell. The cell is more concentrated than its surroundings (hypertonic cell, hypotonic solution), so water enters. Option (A) is incorrect because it claims the cell's Ψ is lower — which is true — but then draws the wrong conclusion: lower Ψ means water flows into the cell, not out.
Water Potential Calculation — Worked Example

A plant cell has Ψs = −10 bars and Ψp = +4 bars. Cell Ψ = −10 + 4 = −6 bars. It is placed in a solution with Ψ = −3 bars.

Since solution Ψ (−3) > cell Ψ (−6), water moves from the solution into the cell (the solution is hypotonic = less concentrated than the cell). As water enters, turgor pressure (Ψp) increases, raising cell Ψ until equilibrium (Ψcell = Ψsolution).

Topic 2.6

Facilitated Diffusion

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Facilitated diffusion is passive transport that uses membrane proteins (channels or carriers) to move large polar molecules or ions down their concentration gradient. Like simple diffusion, it requires no ATP — transport is still driven by the concentration gradient. The proteins simply provide a pathway through the hydrophobic core.

🕳 Channel Proteins

Form a water-filled pore through the membrane. Most are gated — they open and close in response to signals (voltage, ligands, mechanical stretch). Ion channels are highly selective (size and charge of pore matches specific ion). Aquaporins are an example (uncharged channel, highly specific for water).

🔄 Carrier (Transporter) Proteins

Bind to a specific substrate, undergo a conformational change, and release the substrate on the other side. More selective than channels. Slower than channel-mediated transport (must bind and change shape for each molecule). Example: GLUT transporters for glucose into red blood cells.

High-Frequency Exam Points

Facilitated diffusion is still PASSIVE. Even though it uses proteins, no ATP is consumed. The movement is still down the concentration gradient. This is a very common exam trap — do not equate "uses a protein" with "requires energy."

Saturation kinetics: Unlike simple diffusion, facilitated diffusion can be saturated — when all carrier/channel proteins are occupied, increasing concentration further will not increase transport rate. This creates a plateau in a rate vs. concentration graph. This is analogous to enzyme saturation (Michaelis-Menten kinetics).

MCQ · Topic 2.6

A researcher increases the concentration of glucose outside a red blood cell. Initially, glucose transport into the cell increases proportionally, but eventually the transport rate levels off even as glucose concentration continues to rise. Which of the following best explains this observation?

  • (A) The cell has reached its maximum ATP production capacity.
  • (B) The concentration gradient no longer exists at high glucose concentrations.
  • (C) All available GLUT carrier proteins are saturated, so the transport rate cannot increase further.
  • (D) The cell membrane becomes impermeable to glucose at high concentrations.
Answer: (C) — Glucose enters red blood cells via GLUT carrier proteins (facilitated diffusion). When all carrier proteins are occupied (saturated) by substrate molecules, the maximum transport rate (Vmax) is reached. Adding more glucose cannot increase the rate because there are no free carriers available. This is analogous to enzyme saturation. ATP is not involved (A is wrong) — facilitated diffusion is passive.
Topic 2.7

Tonicity and Osmoregulation

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Tonicity describes the relative concentration of solutes in a solution compared to the interior of a cell, and determines the net direction of osmosis. Three terms describe relative tonicity:

TonicityDefinitionEffect on Animal CellEffect on Plant Cell
HypotonicSolution has LOWER solute concentration than cell interiorWater enters → cell swells → may lyse (osmotic lysis / cytolysis). RBCs in pure water → hemolysis.Water enters → turgid (firm). Turgor pressure pushes against cell wall. Normal, desirable state for plant cells.
IsotonicEqual solute concentration — no net osmosisNormal shape maintained. No net water movement.Cell is flaccid (no turgor pressure). Wilted appearance despite no water deficit at cellular level.
HypertonicSolution has HIGHER solute concentration than cell interiorWater exits → cell shrinks / crenates. RBCs become spiky "crenated" cells.Water exits → plasmolysis. Plasma membrane pulls away from cell wall. Cell cannot function.

Why Plant Cells Differ from Animal Cells

Plant cells have a rigid cell wall. When water enters a hypotonic solution, the cell wall resists expansion — building up turgor pressurep). Turgor pressure keeps plants upright. Wilting occurs when turgor pressure decreases (plant cells become flaccid in isotonic or hypertonic conditions) — not because cells lyse. Animal cells lack cell walls and will lyse in hypotonic solutions.

High-Frequency Exam Points

Plasmolysis vs. Crenation: Plasmolysis = plant cell in hypertonic solution (membrane pulls from wall). Crenation = animal cell in hypertonic solution (cell shrinks/spikes). Lysis = animal cell in hypotonic (bursts). Turgid = plant cell in hypotonic (ideal). These four terms appear constantly in osmosis questions.

Contractile vacuoles in freshwater protists (like Paramecium) pump out excess water entering by osmosis from the hypotonic environment. This is an energy-requiring (active) process of osmoregulation.

"Potato / egg / dialysis tubing" lab questions: If a potato slice placed in salt water loses mass → hypertonic solution (water left the potato). If it gains mass → hypotonic solution (water entered potato). Mass change direction = direction of net water movement.

Data-Based · Topic 2.7

A student cuts four equal-sized pieces of potato and places each piece in a solution of different NaCl concentration: 0.0 M, 0.2 M, 0.4 M, and 0.8 M. After 30 minutes, she measures the mass change (%). She observes that the 0.0 M piece gained 8% mass, the 0.2 M piece gained 3%, the 0.4 M piece showed 0% change, and the 0.8 M piece lost 12%. What is the approximate solute concentration of the potato cells?

Answer: ~0.4 M NaCl

The piece with 0% mass change is in an isotonic solution — meaning the solution's solute concentration equals the potato cell's internal solute concentration. No net osmosis occurs. Therefore, the potato cells have a solute concentration approximately equal to 0.4 M NaCl. This type of calculation (finding the isotonic point from a mass change vs. concentration graph) is a classic AP Biology lab question.
Topic 2.8

Mechanisms of Transport — Active Transport & Bulk Transport

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Active transport moves substances against their concentration gradient (from low to high concentration). This is thermodynamically unfavorable and requires an energy source. Primary active transport is directly powered by ATP hydrolysis (e.g., Na⁺/K⁺-ATPase). Secondary active transport is driven indirectly — it uses the electrochemical gradient established by a primary pump (e.g., glucose entering intestinal cells co-transported with Na⁺ flowing down its gradient). Both types require carrier proteins.

The Sodium-Potassium Pump (Na⁺/K⁺-ATPase)

The canonical example of primary active transport. For each ATP hydrolyzed, the pump moves 3 Na⁺ out of the cell and 2 K⁺ in — against both concentration and electrical gradients for each ion. This maintains the resting membrane potential (negative inside) critical for nerve and muscle function.

The pump cycle: (1) Na⁺ binds inside the cell → (2) ATP phosphorylates the pump → (3) conformational change opens pump to outside → (4) Na⁺ released outside, K⁺ binds → (5) dephosphorylation → (6) conformational change → K⁺ released inside. Cycle repeats.

Secondary Active Transport (Co-transport)

Uses the electrochemical gradient established by a pump (e.g., Na⁺/K⁺-ATPase creates a Na⁺ gradient) to drive another molecule against ITS gradient. The Na⁺ gradient is a form of stored potential energy. Example: Sodium-glucose cotransporter (SGLT) in intestinal cells uses Na⁺ flowing down its gradient to drag glucose in against the glucose gradient — even when glucose is already concentrated inside. Indirectly requires ATP (to maintain the Na⁺ gradient).

Bulk Transport — Moving Large Materials

⬇️ Endocytosis

Cell takes material IN by engulfing it with the plasma membrane, forming a vesicle. Phagocytosis ("cell eating") — engulfs large particles (bacteria, food particles). Pinocytosis ("cell drinking") — nonspecific uptake of extracellular fluid. Receptor-mediated endocytosis — specific; ligand binds to receptor → clathrin-coated pit forms → vesicle pinches off (e.g., LDL cholesterol uptake).

⬆️ Exocytosis

Cell secretes material OUT by fusing a vesicle with the plasma membrane. Used for: secreting hormones (insulin from pancreatic β cells), neurotransmitters (into synapse), digestive enzymes, extracellular matrix components. The vesicle membrane becomes part of the plasma membrane.

High-Frequency Exam Points

Passive vs. Active transport comparison: The AP exam frequently asks you to compare them. Key distinction: passive transport moves with the gradient and requires no ATP; active transport moves against the gradient and requires an energy source — either directly from ATP (primary active transport) or indirectly from an ion gradient established by an ATP-driven pump (secondary active transport). Both active and passive transport may use membrane proteins.

Na⁺/K⁺-ATPase creates the membrane potential used in nerve signal transmission (Unit 4). Understanding this pump is foundational for neuroscience questions.

Receptor-mediated endocytosis + LDL: Familial hypercholesterolemia is caused by a defective LDL receptor — LDL cannot be endocytosed → accumulates in blood → cardiovascular disease. This connects biochemistry to disease in a testable scenario.

MCQ · Topic 2.8

A cell is treated with a drug that inhibits ATP synthase, preventing ATP production. Which of the following transport processes would be MOST directly affected?

  • (A) Diffusion of O₂ across the plasma membrane
  • (B) Osmosis of water through aquaporins
  • (C) Facilitated diffusion of glucose via GLUT transporters
  • (D) Active transport of Na⁺ against its concentration gradient via Na⁺/K⁺-ATPase
Answer: (D) — Active transport (Na⁺/K⁺-ATPase) directly requires ATP to phosphorylate the pump and drive its conformational change. Without ATP, the pump cannot function. Simple diffusion (A), osmosis via aquaporins (B), and facilitated diffusion (C) are all passive processes that do not require ATP — they would be unaffected by an ATP synthase inhibitor.
Topic 2.9

Cell Compartmentalization

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Eukaryotic cells are divided into compartments by internal membranes. This compartmentalization is a major advantage — it allows incompatible reactions to occur simultaneously, concentrates enzymes and substrates, and creates specialized microenvironments.

Why Compartmentalization Matters

⚡ Simultaneous Incompatible Reactions

DNA synthesis occurs in the nucleus while protein synthesis occurs in the cytoplasm — these processes are spatially separated. Lysosomal hydrolases work at pH 5 inside lysosomes while the cytoplasm maintains pH 7.2 — without compartmentalization, hydrolases would digest the entire cell.

🎯 Concentration of Reactants

Enzymes of a metabolic pathway are co-localized in a specific organelle (e.g., Krebs cycle enzymes in the mitochondrial matrix). Concentrating reactants in a small space dramatically increases reaction rates — rather than diluting molecules throughout the cytoplasm.

🔋 Electrochemical Gradients

Inner mitochondrial membrane creates a proton (H⁺) gradient used to drive ATP synthesis (chemiosmosis). The thylakoid membrane of chloroplasts does the same. These gradients can only be maintained because membranes create compartments that separate high and low H⁺ concentrations.

🛡 Isolation of Hazardous Contents

Lysosomes isolate hydrolytic enzymes from the rest of the cell. Peroxisomes contain catalase to neutralize H₂O₂ before it damages other cellular components. Compartmentalization prevents cellular self-destruction.

High-Frequency Exam Points

FRQ scenario: "Explain why a cell with a non-functional lysosomal membrane would be harmed." → Hydrolytic enzymes at pH 5 would be released into the cytoplasm (pH 7.2) — the pH would still partially inhibit them, but enough activity remains to digest cytoplasmic proteins, DNA, and organelles → cell death. This is related to lysosomal storage diseases.

Chemiosmosis requires compartmentalization: The proton gradient across the inner mitochondrial membrane (or thylakoid membrane) can only exist because the membrane creates two separate compartments with different H⁺ concentrations. Disrupting the membrane dissipates the gradient and stops ATP synthesis.

Topic 2.10

Origins of Cell Compartmentalization — Endosymbiotic Theory

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The Endosymbiotic Theory (Lynn Margulis, 1967) proposes that mitochondria and chloroplasts originated as free-living prokaryotes that were engulfed by a larger host cell, and instead of being digested, established a mutually beneficial (endosymbiotic) relationship. Over time, the endosymbiont became permanently integrated as an organelle.

Evidence Supporting Endosymbiosis

EvidenceMitochondriaChloroplastsWhy It Supports Endosymbiosis
Circular DNA✅ Circular chromosome✅ Circular chromosomeLike bacteria — not linear like eukaryotic nuclear DNA
Ribosome size✅ 70S ribosomes✅ 70S ribosomesSame size as bacterial ribosomes; 80S in eukaryotic cytoplasm
Double membrane✅ Inner + outer membrane✅ Inner + outer membraneOuter membrane came from the host cell's phagocytic vesicle; inner membrane is the original prokaryote's plasma membrane
Binary fission✅ Divide by binary fission✅ Divide by binary fissionReplicate independently like bacteria — not by the cell cycle
Antibiotic sensitivity✅ Inhibited by bacterial antibiotics✅ Inhibited by bacterial antibiotics70S ribosomes are targets of many antibiotics (e.g., streptomycin); confirms prokaryotic origin
Ancestral relationshipMost similar to α-proteobacteriaMost similar to cyanobacteriaSequence analysis confirms evolutionary relationship to free-living bacteria
Endosymbiosis Sequence

1. Large anaerobic prokaryote (ancestor of eukaryote) engulfs a smaller aerobic α-proteobacterium by phagocytosis.

2. Instead of being digested, the endosymbiont survives inside the host and begins supplying the host with ATP from aerobic respiration (mutually beneficial).

3. Over evolutionary time, genes transfer from the endosymbiont's genome to the host nucleus (gene transfer). The endosymbiont becomes permanently dependent — it is now the mitochondrion.

4. A separate event: a eukaryote engulfs a photosynthetic cyanobacterium → becomes the chloroplast. This happened in the ancestor of plants and algae.

FRQ-Style · Topic 2.10

A student claims that mitochondria originated as free-living bacteria that were engulfed by a eukaryotic ancestor. Provide THREE distinct pieces of evidence that support this claim.

Evidence 1 — Circular DNA: Mitochondria contain their own circular chromosome, similar in structure to bacterial DNA. Eukaryotic nuclear DNA is organized on linear chromosomes with histone proteins, but mitochondrial DNA is circular and not associated with histones — just like bacteria.

Evidence 2 — 70S ribosomes: Mitochondria contain 70S ribosomes, which are the same size and type as bacterial ribosomes. Eukaryotic cytoplasmic ribosomes are 80S. Mitochondrial ribosomes are also sensitive to antibiotics (e.g., chloramphenicol) that inhibit bacterial 70S ribosomes but not eukaryotic 80S ribosomes — reflecting their prokaryotic origin.

Evidence 3 — Double membrane and binary fission: Mitochondria are surrounded by a double membrane — the outer membrane is derived from the host's phagocytic vesicle, while the inner membrane is the original bacterial plasma membrane. Furthermore, mitochondria reproduce by binary fission (like bacteria), dividing independently of the cell cycle — not by mitosis as would be expected for a purely eukaryotic structure.
Exam Prep

Mixed Practice Questions

MCQ · Multi-Topic

A scientist treats cells with cytochalasin D, a drug that disrupts actin microfilaments. Which of the following processes would most likely be affected?

  • (A) Chromosome separation during mitosis
  • (B) Phagocytosis of bacteria by a macrophage
  • (C) Movement of vesicles from ER to Golgi
  • (D) Synthesis of ATP in the mitochondria
Answer: (B) — Phagocytosis requires the plasma membrane to extend pseudopodia around the target (bacteria). Pseudopod extension is driven by actin microfilament polymerization. Disrupting actin would prevent pseudopod formation and thus phagocytosis. Chromosome separation (A) uses microtubules (spindle fibers), not actin. Vesicle transport from ER to Golgi (C) uses microtubules and motor proteins. ATP synthesis (D) is a biochemical process in the inner mitochondrial membrane — unrelated to the cytoskeleton.
FRQ-Style · Multi-Topic

Describe the complete pathway of a secretory protein, from the gene encoding it to its release outside the cell. Name each cellular structure involved and describe what happens at each step.

Step 1 — Nucleus: The gene encoding the secretory protein is transcribed into mRNA. mRNA exits the nucleus through nuclear pores.

Step 2 — Rough ER: Ribosomes on the rough ER translate the mRNA. The protein is threaded into the ER lumen as it is synthesized. Initial folding and glycosylation occur in the ER.

Step 3 — Transport vesicle: The protein is packaged into a transport vesicle that buds from the ER membrane.

Step 4 — Golgi apparatus (cis face → trans face): The vesicle fuses with the cis face of the Golgi. As the protein moves through Golgi cisternae, it is further modified (additional glycosylation, phosphorylation, cleavage). At the trans face, the protein is sorted and packaged into a secretory vesicle.

Step 5 — Secretory vesicle → Plasma membrane: The secretory vesicle moves to the plasma membrane. The vesicle membrane fuses with the plasma membrane (exocytosis), releasing the protein into the extracellular space.
Common Mistakes

High-Frequency Errors to Avoid

Unit Summary

Unit 2 — Key Takeaways

🔬 Cell Structure (2.1)

Prokaryotes: no nucleus, circular DNA, 70S ribosomes. Eukaryotes: membrane-bound organelles. Know the secretory pathway (RER → Golgi → vesicle → outside).

📐 Cell Size (2.2)

SA:V decreases as cell grows. Cells must stay small to efficiently exchange materials. SA = 6s² (cube); SA:V = 6/s. Microvilli, cristae, alveoli all increase SA.

🫧 Plasma Membrane (2.3)

Fluid Mosaic Model: phospholipid bilayer with integral/peripheral proteins, cholesterol, glycoproteins. Fluidity: ↑ unsaturation → ↑ fluidity; cholesterol buffers fluidity.

🚪 Permeability (2.4)

Small nonpolar → freely crosses. Ions/large polar → need proteins. Aquaporins speed water movement. Steroid hormones cross; protein hormones cannot.

⬇️ Passive Transport (2.5–2.6)

Simple diffusion: small nonpolar, no protein, no ATP. Osmosis: water down Ψ gradient. Facilitated diffusion: ions/glucose via channels/carriers, no ATP, saturatable.

💧 Tonicity (2.7)

Hypotonic → water in (turgid plant / lysed animal). Isotonic → no change (flaccid plant). Hypertonic → water out (plasmolysis plant / crenation animal).

⚡ Active Transport (2.8)

Against gradient, requires ATP. Na⁺/K⁺-ATPase: 3 Na⁺ out, 2 K⁺ in. Co-transport: uses Na⁺ gradient for glucose uptake. Endo/exocytosis for bulk material.

🏗 Compartmentalization (2.9–2.10)

Allows simultaneous incompatible reactions; maintains H⁺ gradients for ATP synthesis. Endosymbiosis: mitochondria + chloroplasts from bacteria (circular DNA, 70S ribosomes, binary fission, double membrane).

Unit 2 Exam Strategy

Unit 2 = 10–13% of the AP Biology Exam. The highest-yield topics are: membrane transport (passive vs. active), tonicity and osmosis calculations (including water potential math), the secretory pathway, endosymbiotic theory evidence, and SA:V ratio calculations. Osmosis and tonicity questions appear in almost every exam. Know the difference between turgid/flaccid/plasmolysis (plant) and normal/crenated/lysed (animal) clearly.

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